Q. Find the current through the 10 ohm resistance connected across AB. 

 

Dear Student ,
Applying Kirchoff's law we can write that,10=2I+10I-I1 6I-5I1=5  ....1and 5=I1×1-I-I1×105=11I1-10I  ....2So by solving we get,66I-55I1+55I1-50I=8016I=80I=5Aand I1=30-55=5ASo the current through 10 ohm resistance is ,I-I1=5-5=0 A
Regards

  • 18
Sooner
  • -9
What are you looking for?