Q IN THE FIGURE IS THE CENTRE, ∠AOQ = 90, ∠PBO = 42 FIND AND PQB - Maths - Circles

Question

Q IN THE FIGURE IS THE CENTRE, ∠ AOQ = 90, ∠ PBO = 42
FIND AND PQB

Brijendra Pal · Accepted Answer

Hi, we know that in triangle OB = OP = radius and angle opposite to equal side are equal in a triangle so angle OPB = angle OBP = 42 degreeso using angle sum property in a triangle POB 42+42+angle BOP = 180 angle BOP = 180 - 84 = 96 degreenow PB is common chord and angle POB is the angle at center and angle PQB is angle at circumference in same segment so  angle POB= 2 anglePQB anglePQB= angle POB2=962= 48 degree

Q. IN THE FIGURE IS THE CENTRE, ∠ AOQ = 90, ∠ PBO = 42. FIND AND PQB

Q. IN THE FIGURE IS THE CENTRE, $∠$ AOQ = 90, $∠$ PBO = 42. FIND AND PQB