Q. No. 44
Q. The velocity time graph of a particle moving along a straight line in a given time interval is as shown in figure. Then the particle (with increase in time starting from t = 0 sec.)
(A) speeds up
(B) speeds down
(C) first speeds down and then speeds up
(D) first speeds up and then speeds down
Dear student,
In the above V vs T graph the slope of a straight line is constant. The slope of V vs T graph gives Acceleration .
so the Acceleration is constant...
In the above graph from t=0 to t=t0 negative velocity constantly decreases and positive veloity increases...
It means body velocity is slowing down and becomes ZERO at t=t0 and then velocity is increasing in opposite direction.....
We can say it is speeding up in the same direction.....
In the above V vs T graph the slope of a straight line is constant. The slope of V vs T graph gives Acceleration .
so the Acceleration is constant...
In the above graph from t=0 to t=t0 negative velocity constantly decreases and positive veloity increases...
It means body velocity is slowing down and becomes ZERO at t=t0 and then velocity is increasing in opposite direction.....
We can say it is speeding up in the same direction.....