$$\begin{gathered} Q- {\tan }^2\theta -{\sin }^2\theta ={\tan }^2\theta {\sin }^2\theta \\ Q- \frac{\tan \theta }{1-cot\theta }+\frac{cot\theta }{1-\tan \theta }=sec\theta \cos ec\theta +1 \end{gathered}$$

Dear student
Since you have not mentioned question number so doing as per my understanding.
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