Q. The LCM and HCF of two numbers are 196 and 20 respectively. How many such pair(s) of numbers can be possible?
(A) 0
(B) 1
(C) 2
(D) 3
(E) None of these
Dear student,
We know that
HCF X LCM = The product of 2 nos.
So, LCM has to be a multiple of the HCF which will yield a integer
But 196/20 = 9.8 which is not a integer
So, 0 pairs are possible
Therefore, the answer is at (A).
hope this helps
thumb up plzz.
We know that
HCF X LCM = The product of 2 nos.
So, LCM has to be a multiple of the HCF which will yield a integer
But 196/20 = 9.8 which is not a integer
So, 0 pairs are possible
Therefore, the answer is at (A).
hope this helps
thumb up plzz.