Q. The LCM and HCF of two numbers are 196 and 20 respectively. How many such pair(s) of numbers can be possible?
(A) 0
(B) 1
(C) 2
(D) 3
(E) None of these

Dear student,

We know that 

HCF X LCM = The product of 2 nos.

So, LCM has to be a multiple of the HCF which will yield a integer

But 196/20 = 9.8 which is not a integer

So, 0 pairs are possible

Therefore, the answer is at (A).

hope this helps

thumb up plzz.

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no pairs are possible
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