Q. The letters of the word "PROBABILITY" are placed in a bag and one letter is taken out.
i There are .................... outcomes.
ii What is the probability of the following being the one taken out?
a) P ( P) = .................... (b) P (R) = ............................ (c) P(B) = ..................
d) P (I) = ..................... (e) P (vowels ) = ................... (f) P (consonants) = ...........
g) P (X) = ................... (h) P (any letter) = .................
(i) There are 11 outcomes as there are total of 11 letters in the word "PROBABILITY".
[ii] (a) Probability= Favourable outcomes​
Total Number of outcomes
P(P)= 1/11 (Since 'P' is one in number and total number of outcomes are eleven)
(b) P(R)=1/11(Since'R' is one in number and total number of outcomes are eleven)
(c) P(B)= 2/11(Since 'B' is two in number and total number of outcomes are eleven)
(d) P(I)=2/11(Since'I' is two in number and total number of outcomes are eleven)
(e) P(vowels)= 4/11(Since there are four vowels in number namely two 'I's,one each of 'A' & 'O' and total number of outcomes are eleven)
(f ) P(Consonants)= 7/11(Since there are total of 11 letters out of which 4 are vowels and hence rest are consonants)
(g) P(X)= 0/11( Since 'X' is not there in the word PROBABILITY)
(h) P(any letter)= 11/11=1(Since out of 11 any letter can be picked)
[ii] (a) Probability= Favourable outcomes​
Total Number of outcomes
P(P)= 1/11 (Since 'P' is one in number and total number of outcomes are eleven)
(b) P(R)=1/11(Since'R' is one in number and total number of outcomes are eleven)
(c) P(B)= 2/11(Since 'B' is two in number and total number of outcomes are eleven)
(d) P(I)=2/11(Since'I' is two in number and total number of outcomes are eleven)
(e) P(vowels)= 4/11(Since there are four vowels in number namely two 'I's,one each of 'A' & 'O' and total number of outcomes are eleven)
(f ) P(Consonants)= 7/11(Since there are total of 11 letters out of which 4 are vowels and hence rest are consonants)
(g) P(X)= 0/11( Since 'X' is not there in the word PROBABILITY)
(h) P(any letter)= 11/11=1(Since out of 11 any letter can be picked)