# Q. The letters of the word "PROBABILITY" are placed in a bag and one letter is taken out. i There are .................... outcomes. ii What is the probability of the following being the one taken out?  a) P ( P) = ....................         (b) P (R) = ............................                            (c) P(B) = .................. d) P (I) = .....................          (e) P (vowels ) = ...................                            (f) P (consonants) = ........... g) P (X) = ...................           (h) P (any letter) = .................

(i) There are     11     outcomes as there are total  of 11 letters in the word "PROBABILITY".

[ii]  (a) Probability=  Favourable outcomes​
Total Number of outcomes

P(P)= 1/11  (Since 'P' is one in number and total number of outcomes are eleven)

(b)   P(R)=1/11(Since'R' is one in number and total number of outcomes are eleven)

(c)   P(B)= 2/11(Since 'B' is two in number and total number of outcomes are eleven)

(d)  P(I)=2/11(Since'I' is two in number and total number of outcomes are eleven)

(e)  P(vowels)= 4/11(Since there are four vowels in number namely two 'I's,one each of 'A' & 'O' and total number of outcomes are eleven)

(f ) P(Consonants)= 7/11(Since there are total of 11 letters out of which 4 are vowels and hence rest are consonants)
(g) P(X)= 0/11( Since 'X' is not there in the word PROBABILITY)

(h) P(any letter)= 11/11=1(Since out of  11 any letter can be picked)

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ii)
1. 1/11
2. 1/11
3. 2/11
4. 2/11
5. 4/11
6. 7/11
7. 0/11
8. 11/11
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