Q. The lower end of a capillary tube is dipped in water. Water rises upto height 10 cm. The tube is broken upto 8 cm. Then new angle of contact will be
(1) 53 °
(2) 37 °
(3) 30 °
(4) 0 °

Dear Student

h =2TcosθρrgAs radius and content of tube is same so T, r, g, ρ is constantThereforehcosθ= constanth1h2=cosθ1cosθ2108=cos0cosθ2cosθ2=810=0.8θ2=36.86 =37o
Regards

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