Q19 and Q20(a) Share with your friends Share 0 Vartika Jain answered this Dear Student, 19) According to the question,b = 4vwhere, b is excluded volume of gas moleculev is the actual volume of gas moleculeSo, v= b4=0.0318 Lmol-14= 0.00795 Lmol-1or, v= 0.00795 Lmol-1×1000 cm31 L×mol6.023×103 =1.32×10-23 cm3or, v=43πr3 = 1.32×10-23 cm3where, r is the radius of oxygen atom when oxygen molecule is considered spherical43×227×r3 = 1.32×10-23 cm3r3 = 3.15×10-24 cm3or, r=(3.15×10-24 cm3)13 =1.4659×10-8 cmRadius of oxygen molecule = diameter of oxygen atom=2r =2×1.4659×10-8 cm =2.9318×10-8 cmKindly ask the remaining query in the next thread. 1 View Full Answer
