Dear student the energies of the photons emitted can be expressed as13 6112-122eV =0 6613 6112-132eV =1 8913 6122-132eV =2 55 the transition can be shown as energy of photon transition 1 89 n=3 to n=1 2 55 n=3 to n=2 0 66 n=2 to n=1 so option (D) is correct Regards

Q2.
Ans: B.
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Q2. Ans: B. Help asap. N p amss:an ul pur " S SUJOIE g JO •ou umununu - . V pur • Aa W 0 sati-xau• wutSuo JO D(.urg iO OJ

Dear student

t h e e n e r g i e s o f t h e p h o t o n s e m i t t e d c a n b e e x p r e s s e d a s 13.6 (\frac{1}{1^{2}} - \frac{1}{2^{2}}) e V = 0.66 13.6 (\frac{1}{1^{2}} - \frac{1}{3^{2}}) e V = 1.89 13.6 (\frac{1}{2^{2}} - \frac{1}{3^{2}}) e V = 2.55

the transition can be shown as

energy of photon	transition
1.89	n=3 to n=1
2.55	n=3 to n=2
0.66	n=2 to n=1

so option (D) is correct

Regards

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Q2. Ans: B. Help asap. Q2. Ans: B. Help asap. N p amss:an ul pur " S SUJOIE g JO •ou umununu - . V pur • Aa W 0 sati-xau• wutSuo JO D(.urg iO OJ

Q2.
Ans: B.
Help asap.

Q2. Ans: B. Help asap. N p amss:an ul pur " S SUJOIE g JO •ou umununu - . V pur • Aa W 0 sati-xau• wutSuo JO D(.urg iO OJ