Q2 plz experts give solution
Dear student
Here is the proof for the mentioned result:
Let ABCD is a rectangle such as AB = CD and BC = DA. P, Q, R and S are the mid points of the sides AB, BC, CD and DA respectively.
However, the diagonals of a rectangle are equal.
∴ AC = BD … (5)
By using equation (1), (2), (3), (4), and (5), we obtain
PQ = QR = SR = PS
Therefore, PQRS is a rhombus.
Hope! This will help you!
Regards