Q21: 21. At 550 K, the Kc for the following reaction is 104 mol-1 L. X(g) +Y(g) ⇌ Z(g) At equilibrium, it was observed that X = 1 2 Y = 1 2 Z What is the value of [Z] ( in mol L-1) at equilibrium ? (a) 2 x 10-4 (b) 10-4 (c) 2 x 10-4 (d) 104 Share with your friends Share 5 Geetha answered this For the equilibriumX+Y ↔ZKc = [Z][X][Y]104 =[Z]12[Z]×[Z] since [X]=12[Y] =12[Z] = 112[Z] =2[Z][Z] =2 104 = 2 × 10-4 mol/LThus option a is correct 5 View Full Answer Bhavya answered this Taking conc. Of Z=n at equilibrium So we get X=Z/2 according to question so X=n/2 and, Y=Z so Y=n Rest of solution is in image below Answer is Z=n=2*10^(-4) 1