Q21:

21. At 550 K, the Kc for the following reaction is 104 mol-1 L.
X(g) +Y(g)  Z(g)
At equilibrium, it was observed that 
X = 1 2 Y = 1 2 Z
What is the value of [Z] ( in mol L-1) at equilibrium ?
(a) 2 x 10-4          (b) 10-4               (c) 2 x 10-4         (d) 104





 

For the equilibriumX+Y ZKc = [Z][X][Y]104 =[Z]12[Z]×[Z]  since [X]=12[Y] =12[Z]       = 112[Z] =2[Z][Z] =2 104   = 2 × 10-4 mol/LThus option a is correct

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Taking conc. Of Z=n at equilibrium So we get X=Z/2 according to question so X=n/2 and, Y=Z so Y=n Rest of solution is in image below Answer is Z=n=2*10^(-4)

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