Q25. The potential energy of a particle of mass m is given by $$\begin{gathered} U\left(x\right) = \left\{E_0, 0\le x\le 1\right\} \\ \left\{0, x > 1\right\} \end{gathered}$$ ${\lambda }_1$ and ${\lambda }_2$ are the de-Broglie wavelengths of the particle, when $0\le x\le 1$ and x > 1 respectively. If the total energy of the particle is $2E_0$, the ratio $\frac{{\lambda }_1}{{\lambda }_2}$ will be
(1) 2 : 1                        (2) 1 : 1
(3) $\sqrt{2}$ : 1                    (4) 1 : $\sqrt{2}$