Q72???:
72. How many moles of R will be produced when 8 mol of P and 5 mol of Q are allowed to react according to the equation. 2P+QR.
Dear Student,
2P+QR
Initial : 2P = 8 ,Q = 5 R = 0
Final : P = 4 – 4 Q = 5- 4 (=1) , C = 4
Hence P is the limiting reactant
because its moles (=4) are less than those of Q=5
Final : P = 4 – 4 Q = 5- 4 (=1) , C = 4
Hence P is the limiting reactant
because its moles (=4) are less than those of Q=5
So moles of R is 4 moles will be produced.