Q8

Q8 done to tr,e physics

Dear Student

Work done required to increase velocity of car is equal to increase in kinetic energy
$$\begin{gathered} W=change in kinetic energy =\frac{1}{2}m\left[v^2-u^2\right] \\ W=\frac{1}{2}m\left[v^2-u^2\right] \\ m=1500 kg \\ u = 36\times \frac{5}{18}=10 m/s \\ v = 72\times \frac{5}{18}=20 m/s \\ W=\frac{1}{2}\times 1500\left[400-100\right]=2,25,000J=225kJ \end{gathered}$$
Regards