$$\begin{gathered} Q 87. The IUPAC\hspace{0.17em}name of \begin{array}{ccccccc}& & Cl& & & & \\ & & |& & & & \\ C{H}_3& -& C& -& C{H}_{2}CH& =& CHC{H}_3\\ & & |& & & & \\ & & OH& & & & \end{array} \\ \left(a\right) 5-chloro-2-hydroxyhexene \left(b\right) 2-chloro-5-hydroxyhexene \\ \left(c\right) 2-chloro-2-hydroxy-5-hexene \left(d\right) 2-chloro-4-hexenol-2 \end{gathered}$$

Dear Student,

Please find below the solution of your asked query:

The IUPAC name of the compound given above is 2-Chlorohex-4-en-2-ol.

The numbering of chain begins from the left side of the chain, as the highest priority group present in the chain is alcohol. Now, Chloro group will be named as prefix at second position, then the name of the parent hydrocarbon is written. After that, double bond is named as primary suffix and then finally the secondary suffix is named i.e. alcohol group (having the highest priority).

Therefore, option (d) is correct.

Hope this information clears your doubts about the topic.

Keep asking!!

Regards