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Q9
Plz ans fast
Q.9. The side of a square is 25 cm. Find the length of its diagonal correct to 2 decimal places.

Dear Student,


AC2=AB2+BC2⇒AC2=252+252⇒AC2=625+625⇒AC2=1250⇒AC=35.35

Kindly refer to the similar link to find the root and similar query:
https://www.meritnation.com/ask-answer/question/how-we-can-find-the-value-of-root-2/number-systems/4995390  

https://www.meritnation.com/ask-answer/question/the-side-of-a-square-is-8-cm-find-the-length-of-the-diagona/squares-and-square-roots/8991963 

Regards

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View Full Answer
first consider a square abcd.
now draw the diagonal bd.
now in triangle bcd use pythagoreas theorem.i.e
h(raised to the power 2) = perpendicular(raised to the power 2) + base()raised to the power 2)
                                        = 25(raised to the power 2) + 25(raised to the power 2)
                                         =625+625
                                          =1250
                                           = square root of 1250
                                          =35.35
  • 1
by pythagorus theorum
25^2 + 25^2 =diagonal^2
diagonal= 2(625)^1/2
diagonal= root2 into 25
  • -1
The length of the diagonal is 35.35cm
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