# Q9 Plz ans fast Q.9. The side of a square is 25 cm. Find the length of its diagonal correct to 2 decimal places.

Dear Student,

$A{C}^{2}=A{B}^{2}+B{C}^{2}\phantom{\rule{0ex}{0ex}}⇒A{C}^{2}={25}^{2}+{25}^{2}\phantom{\rule{0ex}{0ex}}⇒A{C}^{2}=625+625\phantom{\rule{0ex}{0ex}}⇒A{C}^{2}=1250\phantom{\rule{0ex}{0ex}}⇒AC=35.35$

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Regards

• -1
first consider a square abcd.
now draw the diagonal bd.
now in triangle bcd use pythagoreas theorem.i.e
h(raised to the power 2) = perpendicular(raised to the power 2) + base()raised to the power 2)
= 25(raised to the power 2) + 25(raised to the power 2)
=625+625
=1250
= square root of 1250
=35.35
• 1
by pythagorus theorum
25^2 + 25^2 =diagonal^2
diagonal= 2(625)^1/2
diagonal= root2 into 25
• -1
The length of the diagonal is 35.35cm
• -1
What are you looking for?