qs 41 plzz
Q.41.
LHS: sq. root of (1-cos A)/(1+cos A)
=sq. root of (1-cos A)(1+cos A)/(1+cos A)(1+cos A)
=sq. root of (1-cos2A)/(1+cos A)2
=sq. root of sin2A/(1+cos A)2
=sin A/(1+cos A) (RHS)
Hence LHS=RHS Proved
=sq. root of (1-cos A)(1+cos A)/(1+cos A)(1+cos A)
=sq. root of (1-cos2A)/(1+cos A)2
=sq. root of sin2A/(1+cos A)2
=sin A/(1+cos A) (RHS)
Hence LHS=RHS Proved