Qs. No. 1 ....???

Dear student,

Kindly find the answer to your query:
$$\begin{gathered} \frac{{\left(\sqrt{2}-2\sqrt{3}\right)}^2-14}{\sqrt{588}-{\displaystyle \frac{5\sqrt{48}}{2}}}\times \sqrt{2} \\ =\frac{2+12-4\sqrt{6}-14}{\sqrt{2\times 2\times 7\times 7\times 3}-{\displaystyle \frac{5\sqrt{2\times 2\times 2\times 2\times 3}}{2}}}\times \sqrt{2} \\ = \frac{-4\sqrt{6}\times \sqrt{2}}{14\sqrt{3}-10\sqrt{3}}= \frac{-8\sqrt{3}}{4\sqrt{3}}= -2 \end{gathered}$$

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