x2 - 2525 - x2 - x2 + 2x=- x2 - 25 x2 - 25 - x2 + 2x=-x22 + 252 - 2 × x2 × 25 - x2 + 2x as, a-b2 = a2 + b2 - 2ab=-x24 + 425 - 2x5 - x2 + 2x=2x5 - x24 - 425 - x2 + 2x=2x5 + 2x - x2 + x24 - 425=12x5 - 5x24 - 425

Ques 13 part 1

Ques 13 part 1 h Of the

(\frac{x}{2} - \frac{2}{5}) (\frac{2}{5} - \frac{x}{2}) - x^{2} + 2 x = - (\frac{x}{2} - \frac{2}{5}) (\frac{x}{2} - \frac{2}{5}) - x^{2} + 2 x = - [{(\frac{x}{2})}^{2} + {(\frac{2}{5})}^{2} - 2 \times \frac{x}{2} \times \frac{2}{5}] - x^{2} + 2 x [as, {(a - b)}^{2} = a^{2} + b^{2} - 2 ab] = - [\frac{x^{2}}{4} + \frac{4}{25} - \frac{2 x}{5}] - x^{2} + 2 x = \frac{2 x}{5} - \frac{x^{2}}{4} - \frac{4}{25} - x^{2} + 2 x = (\frac{2 x}{5} + 2 x) - (x^{2} + \frac{x^{2}}{4}) - \frac{4}{25} = \frac{12 x}{5} - \frac{5 x^{2}}{4} - \frac{4}{25}

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Ques 13 part 1 Ques 13 part 1 h Of the

Ques 13 part 1

Ques 13 part 1 h Of the