Ques 6

Ques 6 94 Q.6 Q.9 (1) Calculations involving mass—mass relationship: In these problems, the mass of one of the reactants/ products is to be calculated if ZnC03 (s) Zn0(s) + C02(g) e.g. Calculate the mass of zinc oxide formed by heating 0.5 mole of zinc carbonate 1 mole of zinc carbonate on heating gives = 81g ofZnO 0.5 mole of zinc carbonate will give = 81 x 0.5 = 40.5 g of ZnO Assignn\ent - VIII In the commercial manufacture Of nitric acid, how many moles of N02 produce 7.33 mol of in the reaction: 3N02(g) + H20 HN03(aq) + NO(g)? How much ofFe can be theoretically obtained by the reduction of 1 kg of Fez03? Calculate the amount ofwater (g) produced by the combustion of 16g methane. How many moles ofmethane are required to produce 22g C02 (g) after combustion? Calculate the mass of 60% H2S04 required to decompose 50g of chalk (calcium carbonate). Which is cheaper: 40% hydrochloric acid at the rate of 50 paise per kilogram or 80% H2S04 at the rate of 25 paise per kilogram to completely neutralize 7 kg of caustic potash? A sample of dolomite contained 45% of CaC03, 40% MgC03 and 15% clay. Calculate the mass of sulphuric acid of 30% strength required to react completely with 10g of sample. Calculate the mass of iron which will be converted into its oxide (Fe304) by the action of 18g of steam on it. What mass of slaked lime would be required to decompose completely 4 grams of ammonium chloride and what would be the mass of each product? Page No: 22

Reaction of HCl with NaOH and H2SO4:

HCl + KOH  → KCl + H2O

36.5  56

H2SO4 + 2KOH →  K2SO4 + 2H2O

  98  56 x 2

It can be seen that

56 g of KOH is neutralized by 36.5 g of HCl

Therefore,

7000 g of KOH will be neutralized by 36.5/56 x 7000 = 4562.5 g = 4.56 Kg HCl

So price of 4.56 Kg HCl = 4.56 x 50 paise = 228 paise

And

56 x 2 = 112 g of KOH is neutralized by 98 g of H2SO4

Therefore,

7000 g of KOH will be neutralized by 98/112  X 7000 = 6125 g = 6.12 Kg of H2SO4

So price of 6.1 Kg H2SO4= 6.1 x 25 paise = 152.5 paise

Thus, H2SO4 is cheaper.

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