Ques tion 14 Share with your friends Share 0 Anand Kumar Pandey answered this Solution : Let PQRS be the rectangular garden.We have, length of the garden PQRS = 16 mbreadth of the garden PQRS = 10 mNow, area of the garden PQRS = 16 × 10 = 160 m2Let x m be the uniform width of concrete walk that is built around the garden.Now, length of the rectangle ABCD = 16+2x mbreadth of the rectangle ABCD = 10+2x mnow, area of ABCD = length × breadth = 16+2x 10+2x = 4x+8x+5 = 4x2+13x+40Now, area of the concrete walk = area of ABCD - area of PQRS⇒120 = 4x2+13x+40 - 160⇒4x2+13x+40 = 280⇒x2+13x+40 = 70⇒x2 + 13x- 30 = 0⇒x2 + 15x - 2x - 30 = 0⇒xx+15 - 2x + 15 = 0⇒x - 2x + 15 = 0⇒x - 2 = 0 or x + 15 = 0⇒x = 2 or x = -15 rejectedSo, uniform width of the concrete walk = 2 m 0 View Full Answer