Ques9 and 10
Dear Student,
9 . Let the width of the frame be x
From Diagram , HG+x+x =DC
20+x+x=28
2x=8
x=4
Area of Trapezium ABEF & DCGH = a+b/2 *h {Where a and b are parallel side and h is height , ie width here}
=20+28/2 * 4
=96 cm2
Area of Trapezium ADHE & BCGF = a+b/2 *h {Where a and b are parallel side and h is height , ie width here}
=24+32/2 * 4
=112 cm2
10 . Area of the the diagram ABCDEFGH = Area of Triangle ABC + Area of Triangle HGF + Rectangle of ADEH
It's clear that ABC & HGF are Right angled triangles , So , AC=HF=3 (as 5, 4 and 3 are pythagorean triplets)
Area of ABC=Area of HGF=1/2*b*h=1/2*4*3=6 cm2
Area of Rectangle ADEH = Length*Width = DE*AD (AD=DC+AC=4+3=7)
=8*7
=56 cm2
Area of the the diagram ABCDEFGH = Area of Triangle ABC + Area of Triangle HGF + Rectangle of ADEH
=6+6+56
=68 cm2
9 . Let the width of the frame be x
From Diagram , HG+x+x =DC
20+x+x=28
2x=8
x=4
Area of Trapezium ABEF & DCGH = a+b/2 *h {Where a and b are parallel side and h is height , ie width here}
=20+28/2 * 4
=96 cm2
Area of Trapezium ADHE & BCGF = a+b/2 *h {Where a and b are parallel side and h is height , ie width here}
=24+32/2 * 4
=112 cm2
10 . Area of the the diagram ABCDEFGH = Area of Triangle ABC + Area of Triangle HGF + Rectangle of ADEH
It's clear that ABC & HGF are Right angled triangles , So , AC=HF=3 (as 5, 4 and 3 are pythagorean triplets)
Area of ABC=Area of HGF=1/2*b*h=1/2*4*3=6 cm2
Area of Rectangle ADEH = Length*Width = DE*AD (AD=DC+AC=4+3=7)
=8*7
=56 cm2
Area of the the diagram ABCDEFGH = Area of Triangle ABC + Area of Triangle HGF + Rectangle of ADEH
=6+6+56
=68 cm2
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
RegardsIf you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.