Ques9 and 10

Ques9 and 10 Four cubes. each or iO edge. end. A S m 30 and 4 m is made em Cm X 7. S If or the total volume of the wan o' how in the Wan? The dimensions or a metal are 2.2 S m by s m by cubes. each Of side 45 Ctn. How many cubes are formed? 97. A closed metallic cylindrical box is 1.25 m high and has a base whose ramus the sheet of metal costs Rs 00 per mz. then find the cost of the material used find the capacity of the box in litres. curved surface area of a cylindrical pillar is 264 mi and its volume is ms me diameter and height of the pillar. Q9. The given figure shows the diagram of a picture frame having outer dimensions cm\" 32 Cm and the inner dimensions 20 cm by 24 cm. the width of each section is me same, find the area of each section of the frame. 10. Find the area of given figure ABCDEFGH as per 5 •c 4 cm 41

Dear Student,

9 . Let the width of the frame be x

From Diagram , HG+x+x =DC
                          20+x+x=28
                          2x=8 
                           x=4

​​​​​​Area of Trapezium ABEF & DCGH = a+b/2 *h {Where a and b are parallel side and h is height , ie width here}​​​
                                                        =20+28/2 * 4
                                                        =96 cm2
​​
​​​Area of Trapezium ADHE & BCGF = a+b/2 *h {Where a and b are parallel side and h is height , ie width here}​​​
                                                        =24+32/2 * 4
                                                        =112 cm2


10 .  Area of the the diagram ABCDEFGH = Area of Triangle ABC + Area of Triangle HGF + Rectangle of ADEH 

It's clear that ABC & HGF are Right angled triangles , So , AC=HF=3 (as 5, 4 and 3 are pythagorean triplets)

Area of ABC=Area of HGF=1/2*b*h=1/2*4*3=6 cm2

Area of Rectangle ADEH = Length*Width = DE*AD     (AD=DC+AC=4+3=7) 
                                                                   =8*7
                                                                   =56 cm2

Area of the the diagram ABCDEFGH = Area of Triangle ABC + Area of Triangle HGF + Rectangle of ADEH 
                                                            =6+6+56
                                                            =68 cm
 
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In rectangle ABCD all are trapezium and as we know the area of trapezium is = to half x sum parallel sides x perpendicular height and E F G H is a rectangle
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Line AC is equals to 4 cm and HF is also equals to 4 cm so now ABC is a triangle and hfg is another Triangle and ahgd is a rectangle now area is equals to area of a b c + area of hfg + ahgd
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