# Question 15 and 16 plss

The reaction is as follows:

2 ZnS(s) + 3 O

_{2}(g) $\to $ 2 ZnO + 2 SO

_{2}

we see that 2 moles of ZnS gives 2 moles of ZnO and 2 moles of SO

_{2}. So,

Number of moles of ZnS = $\frac{Givenmass}{molarmass}=\frac{4.866}{97.474}=0.0499moles$

Mass of ZnO = 81.408 $\times $0.0499 = 4.045 g

Mass of SO

_{2}= 64.06 $\times $ 0.0499 = 3.19 g.

For further query please ask in separate thread.

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