Question) Construct an isosceles triangle with perimeter as 12 cm and height as 3 cm.

Dear Student ,
 
Please find below the solution to the asked query :

Steps of construction :1 Draw a line segment XY=12 cm.2 Draw perpendicular bisector of XY and cut off it at 3 cm and name it as AD.3 Join AX and AY .4 Draw perpendicular bisector of AX and AY .5 The point of intersection of bisectors of AX and AY at CY be  B and C.6 Join AB and AC.Thus , ABC is the required triangle .



Justification:In BPX and BPAPX=PA        Since BP is perpendicular bisectorBPX=BPA     Each 90°BP=BP    CommonBy SAS congruency criterionBPX  BPABX=BA   ... 1Similarly , In CQY and CQACY=CA   ... 2Now ,XY=12 cm   By constructionBX+BC+CY=12BA+BC+CA=12       Using 1 and 2Perimeter of ABC=12 cm .Hence Proved .
 
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