Question) Find the value of ''Q'' in the following.
$Q = {(x \frac{1}{a - b})}^{\frac{1}{a - c}} X {(x \frac{1}{b - c})}^{{\frac{1'}{b - a}}^{}} X {(x \frac{1}{c - a})}^{\frac{1}{c - b}}$

Question

Question) Find the value of ''Q'' in the following
Q = x 1 a - b 1 a - c   X   x 1 b - c 1 ' b - a   X
  x 1 c - a 1 c - b

Shruti Tyagi · Accepted Answer

Dear student,

Assuming the question is "Q=x1a-b1a-c×x1b-c1b-a×x1c-a1c-b"We have,Q=x1a-b1a-c×x1b-c1b-a×x1c-a1c-b=x1a-b×1a-c×x1b-c×1b-a⏟×x1c-a×1c-b=x1a-b×1a-c-1b-c×1a-b  ×x1c-a×1c-b            --[using am×an=am+n]=xb-c-a+ca-ba-cb-c×x1c-a×1c-b                             --[taking LCM in the bracket ]=xb-aa-ba-cb-c×x1c-a×1c-b=x-(a-b)a-ba-cb-c×x1c-a×1c-b                            --[taking -ve common from the Nr and cancelling (a-b)]=x-1a-cb-c×x1c-a×1c-b=x-1a-cb-c+1c-ac-b                                         --[using am×an=am+n]=x-1a-cb-c+-1c-ab-c                                         --[taking -ve common from (c-b) we get (b-c)]=x--1-1c-ab-c                                                               --[taking LCM in the bracket ]=x1-1c-ab-c=x0=1                                                                                    --[using a0=1]

Regards

Question) Find the value of ''Q'' in the following. Q = x 1 a - b 1 a - c X x 1 b - c 1 ' b - a X x 1 c - a 1 c - b

Question) Find the value of ''Q'' in the following.
$Q = {(x \frac{1}{a - b})}^{\frac{1}{a - c}} X {(x \frac{1}{b - c})}^{{\frac{1'}{b - a}}^{}} X {(x \frac{1}{c - a})}^{\frac{1}{c - b}}$