Question no 2

Question no 2 Similarly, we can prove that MS NQ In the quadrilateral SMQN , since MQ = NS and MS NO, therefore EXERCISE II(A) I. ABCD is a parallelogram. From A and B perpendiculars AP and BQ are drawn to meet CD or CD produced. Prove that AP = BQ. 2. E and F are the mid-points of AB and AC tu.'0 sides of a AABC. P is any point on BC. AP cuts EF at Q. Prove that AQ = PQ. . E and F are the mid-points of sides AB and CD respectively of a parallelogram ABCD. Prove that AEFD is a parallelogram. ABCD is a parallelogram and its diagona intersect each other at O. Through O,

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