Question number-18

18. For what values of x and y are the numbers 3 + ix2y and x2+ y + 4i conjugates complexes ?

Complex conjugate of 3+i.x2y is 3-i.x2y where x and y are real.
It is given that complex conjugate of 3+i.x2y is x2+y+i.4
therefore,
3-i.x2y=x2+y+i.4
comparing the real and imaginary parts, we have:

x2+y=3 ........(1) x2y=-4 ..........(2)y=-4x2now, from 1, we getx2-4x2=3x4-3x2-4=0x4-4x2+x2-4=0x2(x2-4)+1(x2-4)=0(x2-4)(x2+1)=0x2-4=0 or x2+1=0x2=4 or x2=-1Rejected

x=±2 since x is a real number

therefore 2 and -2 are two values of x and 

y=-4x2=-44=-1

hope this helps you

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