Question number 18 Q18. Given an acute triangle ABC such that sin C = 4 5 , tan A = 24 7 and AB = 50. The area of the triangle ABC (A) 600 (B) 1200 (C) 1800 (D) 2400 Share with your friends Share 0 Ghanshyam Dhakar answered this Dear student, tanA = BDAD=247⇒AD=7BD24 ...1sinA = 24242+72 = 2425=BDABBD = 2425AB=24×5025=48sinC = BDBC=45⇒cosC = 35tanC=43=BDDCDC=34BD = 34×48 = 36AD=7BD24 = 724×48=14area =12AC×BD = 12AD+DC×BD = 1236+14×48 = 1200 Regards 0 View Full Answer