Question number 30

Dear Student,
Please find below the solution to the asked query:

fx=y=xxTake log with base e on both sideslny=lnxxlny=x.lnxDifferentiate with respect to x1y.dydx=x.ddxlnx+lnx.ddxx1xx.dydx=x.1x+lnx.1dydx=xx1+lnxFor critical pointdydx=01+lnx=0lnx=-1x=e-1=1eSign change of dydx is given by:------1e+++++Hence function is increasing when x>1e...OptionA

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