Question : Q If x = 253 - 53 +1, then find the numerical value of - Maths - Exponents and Powers

Question

Question :

Q     I f   x   =   25 3   -   5
3   + 1 ,   t h e n   f i n d   t h e   n
u m e r i c a l   v a l u e   o f   6 - x x 9

∙ Experts: Please take time as much you required, but most
importantly please write the law used in each step and also
write a proper reason used in writing each step

Ankita Agarwal · Accepted Answer

Dear Student,

Q
 x=253-53+1 then we put value of x in the given expression 6-xx9So, we get=6-253-53+1253-53+19=6-253+53-1253-53+19=6-2513+513-12513-513+19           we can write ba=b1a    By powe rule=5-52×13+51352×13-513+19=5-523+513523-513+19=513523-513+1523-513+19=5139                                            Using: abc = ab×c=593=53=125Hence Option D is correct
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Question : Q . I f x = 25 3 - 5 3 + 1 , t h e n f i n d t h e n u m e r i c a l v a l u e o f 6 - x x 9 . ∙ Experts: Please take time as much you required, but most importantly please write the law used in each step and also write a proper reason used in writing each step.