Dear Student , Hence the fundamental frequency is , f=12LTμNow , 440=12LTμNow when , L'=L5 then ,f'=12L'Tμ⇒f'=52LTμ⇒f'=5×440=2200 Hz Regards

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Dear Student ,

H e n c e t h e f u n d a m e n t a l f r e q u e n c y i s, f = \frac{1}{2 L} \sqrt{\frac{T}{μ}} N o w, 440 = \frac{1}{2 L} \sqrt{\frac{T}{μ}} N o w w h e n, L' = \frac{L}{5} t h e n, f' = \frac{1}{2 L'} \sqrt{\frac{T}{μ}} \Rightarrow f' = \frac{5}{2 L} \sqrt{\frac{T}{μ}} \Rightarrow f' = 5 \times 440 = 2200 H z

Regards

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