Dear Student, Apparent weight, W'=F+W-Bwhere, F is the force due to surface tensionW'=S×2l+t+W-V2ρgW'=72×10-3×2×0 1+0 002+8×10-3-0 1×15×10-3×2×10-32×103×9 8W'=14 688×10-3+8×10-3-14 7×10-3W'=22 688×10-3-14 7×10-3=7 988×10-3 N

Question-
Question- A glass p'ate of length 0 1 m, breadth 15 100 m and thickness 2 10-2 m weighs 8 kg in air. it is held vertically with its longer Side horizontal and its 'ower immersed in water. the surface tension of water is 72 * 10-3 N/m, the apparent weught of the wilt be (D) 79 4 x N (C) 722* (A) IOAN (B) 36

Dear Student,

Apparent weight, W' = (F + W) - B where, F is the force due to surface tension W' = [S \times 2 (l + t) + W] - \frac{V}{2} ρg W' = [72 \times 10^{- 3} \times 2 \times (0.1 + 0.002) + 8 \times 10^{- 3}] - \frac{0.1 \times 15 \times 10^{- 3} \times 2 \times 10^{- 3}}{2} \times 10^{3} \times 9.8 W' = [14.688 \times 10^{- 3} + 8 \times 10^{- 3}] - 14.7 \times 10^{- 3} W' = 22.688 \times 10^{- 3} - 14.7 \times 10^{- 3} = 7.988 \times 10^{- 3} N

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