rectangle ABCD and triangle ABE are inscribed in the circle with centre O. If O is the centre of rectangle and ∠AEB = 40°, then ∠BOC​

AEB = ADB (ANGLE IN SAME SEGMENT)
BDC = ADC -ADB
BDC =90° - 40°= 50°
BOC =2 × BDC ( angle subtended in centre is double the angle on the circumference )
So BOC =2 × 50° = 100°

So the answer is 100°

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