Respected authorities pls solve this question step wiseA block B is pushed momentarily along a horizontal surface with an initial velocity
V. Ifμ is the coefficient of sliding friction between B and the surface, block B will come
to rest after a time
- A)
V/g
- B)
V/(gμ)
- C)
(gμ)V/
- D)
g/V
Let the mass of the block be ‘m’. So, frictional force on the block when sliding is, f = μmg
And the retardation is = μg
Its initial velocity is v. So, the time taken by the block to come to rest is,
t = v/(μg)