Respected authorities pls solve this question step wiseA block B is pushed momentarily along a horizontal surface with an initial velocity

V. Ifμ is the coefficient of sliding friction between B and the surface, block B will come

to rest after a time

  • A)

    V/g

  • B)

    V/(gμ)

  • C)

    (gμ)V/

  • D)

    g/V

Let the mass of the block be ‘m’. So, frictional force on the block when sliding is, f = μmg

And the retardation is = μg

Its initial velocity is v. So, the time taken by the block to come to rest is,

t = v/(μg)

 

  • 14
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