Rs.427.50 was paid as interest on Rs.3050.If the rate was 6%p.a and the amount was borrowed on January 10,2001,what was the date on which the loan was recovered?Answer is 10th July,2003.Show the process.

Dear Student,


The interest paid is given incorrectly in the question it is 457.50 and not 427.50Simple interest=PRT100Putting values in above formula457.50=3050×6×T100457.50×100=3050×6×T45750=3050×6×TT=457503050×6T=4575018300=457.5183=2.5 yearshence we get 2 years and 6 monthsthus january 10, 2003 the 2 years will be completednext 6 months will be covered on july 10, 2003.If the interest was 427.50then T=427.50183=2.336 Yearsby jauary 10, 2003 the 2 years are coverednow converting 0.336 years into days, we get0.336×365=122.66Hence 122 days after january 10, 2003we can covere 21 days in jan, 28 in feb,31 in march, 30 in apr=110 daysrest 12 days will be covered in mayHence date of recovery =12th may 20043 which is not matching with your answer.Hence correct interest amount is 457.5 and date of recovery is july 10, 2003.

Regards,

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