Rs.427.50 was paid as interest on Rs.3050.If the rate was 6%p.a and the amount was borrowed on January 10,2001,what was the date on which the loan was recovered?Answer is 10th July,2003.Show the process. Share with your friends Share 0 Shruti Tyagi answered this Dear Student, The interest paid is given incorrectly in the question it is 457.50 and not 427.50Simple interest=PRT100Putting values in above formula457.50=3050×6×T100457.50×100=3050×6×T45750=3050×6×TT=457503050×6T=4575018300=457.5183=2.5 yearshence we get 2 years and 6 monthsthus january 10, 2003 the 2 years will be completednext 6 months will be covered on july 10, 2003.If the interest was 427.50then T=427.50183=2.336 Yearsby jauary 10, 2003 the 2 years are coverednow converting 0.336 years into days, we get0.336×365=122.66Hence 122 days after january 10, 2003we can covere 21 days in jan, 28 in feb,31 in march, 30 in apr=110 daysrest 12 days will be covered in mayHence date of recovery =12th may 20043 which is not matching with your answer.Hence correct interest amount is 457.5 and date of recovery is july 10, 2003. Regards, 0 View Full Answer