sec theta=m and tan theta=n , then find 1/m[(m+n)+1/(m+n)] Share with your friends Share 3 Anuradha Sharma answered this secθ=m and tanθ=n, so1mm+n+1m+n=1mm+n2+1m+n=1mm2+n2+2mn+1m+n=1secθsec2θ+tan2θ+2secθtanθ+1secθ+tanθNow we know that sec2θ-tan2θ=1=1secθsec2θ+tan2θ+1+2secθtanθsecθ+tanθ=1secθ2sec2θ+2secθtanθsecθ+tanθ=2secθsecθsecθ+tanθsecθ+tanθ=2 5 View Full Answer
