Show that cos2x - cos3x - cosx =0 For x= 2π/7

Dear student

cos2x-cos3x-cosx=cos2x-cos3x+cosx=cos2x-2cos3x+x2cos3x-x2       as cosA+cosB=2cosA+B2cosA-B2=cos2x-2cos2x cosx=cos2x(1-2cosx)=cos2×2π71-2cos2π7=cos4π71-2cos2π7Please recheck the question because for x=2π7 we cannot get the desired result.
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