show that, if the 3 digit number in the form of 906 (i.e. digit at tens place is 0) is subtracted from the sum of its digits, we always get a number divisible by 11

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  • -1
 the number is 906.
so sum of its digit =9+6=15
906-15=891
now if we divide 891 by 11, we get 81 as the answer.

hope it helps you out!!!
  • 3
The three digit no. is 906. And the sum is 9+0+6=15 We have to show that if a three digit no. is subtracted from the sum of the digits then we always get a number divisible by 11. After subtracting it ,we get 906-15=891 891/11=81 I hope this will help you
  • 5
Show that if three digit number is in the form of 906 is subtracted from the sum of its digit we always get a number divisible by 11
  • -1
Let us take 906 ... So, sum of its digit = 9+0+6 = 15 ,  
So, if we subtract it by 906 we get, 906-15 = 891,
And, 891/11 = 81 
So, proved that when a three digit number having 0 at tens place is divided by 11 always...
  • 1
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