show that, if the 3 digit number in the form of 906 (i.e. digit at tens place is 0) is subtracted from the sum of its digits, we always get a number divisible by 11

the number is 906.
so sum of its digit =9+6=15
906-15=891
now if we divide 891 by 11, we get 81 as the answer.

hope it helps you out!!!

2

javalam619... answered this

The three digit no. is 906.
And the sum is 9+0+6=15
We have to show that if a three digit no. is subtracted from the sum of the digits then we always get a number divisible by 11.
After subtracting it ,we get
906-15=891
891/11=81
I hope this will help you

5

Kumkum answered this

Show that if three digit number is in the form of 906 is subtracted from the sum of its digit we always get a number divisible by 11

-1

Rudransh Tiwari answered this

Let us take 906 ... So, sum of its digit = 9+0+6 = 15 ,
So, if we subtract it by 906 we get, 906-15 = 891,
And, 891/11 = 81
So, proved that when a three digit number having 0 at tens place is divided by 11 always...