Show that if x is real , the expression x2-bc/ 2x-b-c has no real value between b and c.

As *x* is real, so D > 0.

This is possible only when either both terms are (+)ve or both (–)ve.

(*y* – *c*) (*y* – *b*) = (+)ve, when *y* > *c* and *y* > *b*

(*y* – *c*) (*y* – *b*) = (–)ve, when *y* < *c* and *y* < *b*

Hence, the given expression has no real value between *b* and *c*.

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