show that sin^-1 (2x(root)1-x^2)=2sin^-1 x

Let x = sinθ, then sin-1x =θ. we have sin-1(2x1-x2) = sin-1(2sinθ1-sin2θ) =sin-1(2sinθcosθ)= sin-1(sin2θ) = 2θ = 2sin-1x Hence proved

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