Show that sin3(180 degree+A) . tan(360 degree-A) . sec2(180 degree-A) / cos2(90 degree-A)cosec2A . sin(180 degree-A ) = tan3A

sin3180+Atan360-Asec2180-Acos290-Acosec2Asin180-A= -sin3A×-tanA×cosec2Asin2A×cosec2A×sinA= -tanABut RHS is different so please recheck the question

  • -21
What are you looking for?