show that the equation of the tangent to the curve x2/a2+y2/b2=1 at (xo,yo) is xxo/a2+yyo/b2=1 - Maths - Application of Derivatives

Question

show that the equation of the tangent to the curve
x2/a2+y2/b2=1 at (x
o ,y o ) is
xxo/a2+yyo/b 2 =1

Hari Shankar · Accepted Answer

Dear student

â€‹â€‹â€‹â€‹â€‹â€‹we
take x1 and y1 in place of x0 and y0
<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ck_5b404824c1377%20png">

Regards

show that the equation of the tangent to the curve x2/a2+y2/b2=1 at (x o ,y o ) is xxo/a2+yyo/b 2 =1

show that the equation of the tangent to the curve x²/a²+y²/b²=1 at (x_o,y_o) is xx_o/a²+yy_o/b²=1