simplest form of tan-1 (3cosx-4sinx/4cosx+3cosx)=

Dear Student,
Please find below the solution to the asked query:

Let y=tan-13cosx-4sinx4cosx+3sinx=tan-134-tanx1+34tanx                               Dividing numerator and denomiator by 4cosx=tan-1tantan-134-tanx1+tantan-134tanx          As, tantan-134=34=tan-1tantan-134-x                      Using: tanx-y=tanx-tany1+tanxtany=tan-134-x

Hope this information will clear your doubts about the topic.
Regards

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