Dear Student , Please find below the solution to the asked query : 23 × 24 × 3212=213 × 214 × 32112 Since an=a1n =213 × 214 × 25112=213 × 214 × 25×112 Since amn=am×n =213 × 214 × 2512=213+14+512 Since am×an=am+n =24+3+512=21212=2 ANS Hope this information will clear your doubts about the topic If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible Regards

Simplify pls this.

Dear Student ,

Please find below the solution to the asked query :

\sqrt[3]{2} \times \sqrt[4]{2} \times \sqrt[12]{32} = {(2)}^{\frac{1}{3}} \times {(2)}^{\frac{1}{4}} \times {(32)}^{\frac{1}{12}} (Since \sqrt[n]{a} = a^{\frac{1}{n}}) = {(2)}^{\frac{1}{3}} \times {(2)}^{\frac{1}{4}} \times {(2^{5})}^{\frac{1}{12}} = {(2)}^{\frac{1}{3}} \times {(2)}^{\frac{1}{4}} \times 2^{5 \times \frac{1}{12}} (Since {(a^{m})}^{n} = a^{m \times n}) = {(2)}^{\frac{1}{3}} \times {(2)}^{\frac{1}{4}} \times 2^{\frac{5}{12}} = 2^{\frac{1}{3} + \frac{1}{4} + \frac{5}{12}} (Since a^{m} \times a^{n} = a^{m + n}) = 2^{\frac{4 + 3 + 5}{12}} = 2^{\frac{12}{12}} = 2 ANS . . .

Hope this information will clear your doubts about the topic .

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible .

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