(sin theta + sec theta)whole square + (cos theta + cosec theta) whole square= (1+sec theta*cosec theta) whole square Share with your friends Share 33 Lovina Kansal answered this Dear student We have,sinθ+secθ2+cosθ+cosecθ2=sinθ+1cosθ2+cosθ+1sinθ2=sin2θ+1cos2θ+2sinθcosθ+cos2θ+1sin2θ+2cosθsinθ=sin2θ+cos2θ+1cos2θ+1sin2θ+2sinθcosθ+cosθsinθ=1+sin2θ+cos2θsin2θcos2θ+2sin2θ+cos2θsinθ cosθ=1+1sin2θcos2θ+21sinθ cosθ=1+1sinθ cosθ2=1+secθ cosecθ2 153 View Full Answer
