Sin theta=( sin 3 theta )/( 1 + 2 cos 2 theta) Share with your friends Share 4 Neha Sethi answered this Dear student We have,sin3θ1+2cos2θ=3sinθ-4sin3θ1+21-2sin2θ ∵sin3x=3sinx-4sin3x and cos2x=1-2sin2x=sinθ3-4sin2θ1+2-4sin2θ=sinθ3-4sin2θ3-4sin2θ=sinθ Regards 5 View Full Answer Fahim Basheer answered this R.H.S = sin 3ϴ / 1+ 2cos 2ϴ 3sinϴ - 4sin3 ϴ/ 1 + 2(1-2sin2ϴ) Sinϴ (3-4 sin2 ϴ) / 1+2 - 4sin2ϴ Sinϴ (3-4 sin2 ϴ)/ (3- 4sin2ϴ) = Sin ϴ L.H.S = Sinϴ Hence Proved... Hope it helps... 4 Divija answered this ans given -6
