Login

sin60/cos2 45 - cot30+ 15 cos 90

$\frac{\sin 60^{0}}{\cos^{2} 45^{0}} - \cot 30^{0} + 15 \cos 90^{0} = \frac{\frac{\sqrt{3}}{2}}{{(\frac{1}{\sqrt{2}})}^{2}} - \sqrt{3} + 15 \times (0) = \frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}} - \sqrt{3} + 0 = \sqrt{3} - \sqrt{3} = 0 H e n c e, \frac{\sin 60^{0}}{\cos^{2} 45^{0}} - \cot 30^{0} + 15 \cos 90^{0} = 0$

-1

View Full Answer

Copyright © 2024 Aakash EduTech Pvt. Ltd. All rights reserved.

Aakash EduTech Pvt. Ltd.

What are you looking for?