Sir/Madam can you please solve question no. 9

Sir/Madam can you please solve question no. 9 9. In the figure find: (ii) area of the trapezium ABCD. 8 cm 2 cm (ICSE)

Dear Student,


Using pythagoras theorem in right angled triangle EDC,hypotenuse2 = base2+perpendicular2102 = EC2+ED2EC2 = 102-62EC = 100-36EC = 64EC = 8 cmi So, AB = 8 cmArea of right angled riangle EDC= 12×base×perpendicular= 12×8×6= 24 cm2Area of rectangle ABCE = 2×8Area of rectangle ABCE = 16 cm2ii Total Area of trapezium ABCD = 24+16 = 40 cm2

Regards

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