Solution of question 2 and 3

Dear Student,
Please find below the solution to the asked query:

The are 10 red balls of different shades.First we will arrange these 10 balls.Number of ways=10!Now after arrnaging these 10 red balls, we will get 11 vacant spaces.We have to arrange 9 green balls in these 11 places.But as these balls are of idenitcal shades, hence we just need to select9 places and need not worry about arrangements.Number of ways to select 9 places from 11=11C9Hence:Total ways=10!×11C9

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