Solve :
2/3 (x) + x^3 - 2x^2 is greater than or equal to 3

Dear student,

Kindly find the answer to your query:
$$\begin{gathered} \mathrm{Assuimg} \mathrm{that} \mathrm{expression} \mathrm{is} : \\ \frac{2}{3}\mathrm{x}+{\mathrm{x}}^3-2{\mathrm{x}}^2>3 \\ 3{\mathrm{x}}^3-6{\mathrm{x}}^2+2\mathrm{x}-9>0 \\ \mathrm{Now} \mathrm{plotting} \mathrm{the} \mathrm{graph} \mathrm{of} 3{\mathrm{x}}^3-6{\mathrm{x}}^2+2\mathrm{x}-9 \mathrm{by} \mathrm{putting} \mathrm{values} \mathrm{of} \mathrm{x} \mathrm{for} \mathrm{y} \mathrm{we} \mathrm{get} \end{gathered}$$

So for values x>2.283 the function attains positive values.

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